[tex] \dfrac{\frac{4t^2 - 16}{8}}{\frac{t - 2}{6}} = [/tex]
[tex] = \dfrac{\frac{4(t^2 - 4)}{8}}{\frac{t - 2}{6}} [/tex]
[tex] = \dfrac{\frac{(t + 2)(t - 2)}{2}}{\frac{t - 2}{6}} [/tex]
[tex] = \dfrac{(t + 2)(t - 2)}{2} \times \dfrac{6}{t - 2} [/tex]
[tex] = \dfrac{t + 2}{1} \times \dfrac{3}{1} [/tex]
[tex] = 3(t + 2) [/tex]
Answer: Choice A.
