emilyabbey455 emilyabbey455

24-05-2022
Mathematics

contestada

Fill in the blank with a number to make the expression a perfect square. v^2-6v+ blank

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KarkiDikshya01 KarkiDikshya01

24-05-2022

Answer:

The blank expression must be

[tex] {3}^{2} [/tex]

because

[tex] {v}^{2} - 6v + blank \\ = {v}^{2} - 2 \times v \times 3 + { 3}^{2} \\ = {(v - 3)}^{2} [/tex]

hope this helps:)

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