The correct answer is: AC = [tex]9 \sqrt{3} [/tex]
Explanation:
Since
[tex]sin(\theta) = perpendicular/hypotenuse [/tex]
Here
[tex]\theta[/tex] = 60°
Perpendicular = x = ?
Hypotenuse = AB = 18
So
Perpendicular = A = sin(60)*18
x = AC = [tex]9 \sqrt{3} [/tex]
