pH = -log[H₃O⁺] 3.6 = -log[H₃O⁺] [H₃O⁺] = antilog (-3.6)
[H₃O⁺] = 2.51 x 10⁻⁴ M
Hence the [H₃O⁺] in given fruit juice is 2.51 x 10⁻⁴ M.
If the pH > 7, then the solution is basic. If the pH < 7, then the solution is acidic.If the pH = 7, then the solution is neutral.
According to the pH, since the juice has pH value as 3.6, it is a slightly acidic solution.
