The answer is 84.
Theorem used: Tangents drawn from the same external point are congruent to each other.
Explanation:
Given JA = 14, AL = 15, CK = 13
JB shares the same external point as JA, therefore JB = 14
CL shares the same external point as AL, therefore CL = 15
BK shares the same external point as CK, therefore BK = 13
Adding all of these values up gives you that the triangle has a perimeter of 84.
