8emilyyoung8
8emilyyoung8
26-03-2018
Mathematics
contestada
what is the length of ab
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altavistard
altavistard
31-03-2018
Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
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