Given mass of silver = 10 g
Initial temperature = [tex] 10^{0}C [/tex]
Final temperature = [tex] 300^{0}C [/tex]
Temperature change ΔT = [tex] T_{final}-T_{initial} = 300^{0}C-10^{0}C [/tex]
= [tex] 290^{0}C [/tex]
Specific heat of silver, C = [tex] 0.235 \frac{J}{^{0}C.g} [/tex]
The relation between heat, mass, specific heat and temperature change is,
[tex] Heat(q) = m C( [/tex]ΔT)
Heat = [tex] 10. g(0.235\frac{J}{^{0}C}(290^{0}C) [/tex]
= 681.5 J
