How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N

6 Li + N2 = 2 Li3N

6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------> ?

moles Li3N = 0.24 * 2 / 6

= 0.48 / 6

= 0.08 moles of li3N

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BarrettArcher BarrettArcher · Answer 2 · 2019-04-09T13:29:33+02:00

Answer : The number of moles of [tex]Li_3N[/tex] will be, 0.08 moles

Solution : Given,

Moles of Li = 0.24 mole

The given balanced chemical reaction is,

[tex]6Li+N_2\rightarrow 2Li_3N[/tex]

From the balanced reaction, we conclude that

As, 6 moles of Li react to gives 2 moles of [tex]Li_3N[/tex]

So, 0.24 moles of Li react to gives [tex]\frac{2}{6}\times 0.24=0.08[/tex] moles of [tex]Li_3N[/tex]

Therefore, the number of moles of [tex]Li_3N[/tex] will be, 0.08 moles