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Determine the osmotic pressure of a solution that contains 0.048 g of a hydrocarbon solute (molar mass = 340 g/mol0

Respuesta :

zelinsky
m(CH) = 0.048 g
M(CH) = 340 g/mol
V = 350 mL = 0.35 L
T = 20 C = 293 K
π = ?

For determination of osmotic pressure we will use next equation:

π = c x R x T

c = n/V

n= m/M = 0.048/340= 0.00014 mol

c = 0.00014/0.35 = 0.0004 mol/L

π =  0.0004 mol/L × 8.314 LkPa/Kmol × 293 K

π = 0.97 kPa


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