Seudónimo Seudónimo

23-07-2014
Mathematics

contestada

Solve by completing the square
x^2-2x-5=0

Respuesta :

konrad509 konrad509

23-07-2014

[tex] x^2-2x-5=0 \\ x^2-2x+1-6=0\\ (x-1)^2=6\\ x-1=\sqrt6 \vee x-1=-\sqrt6\\ x=1+\sqrt6 \vee x=1-\sqrt6 [/tex]

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