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What is the equation of the line described below written in slope-intercept form?

the line passing through point (2, 2) and perpendicular to the line whose equation is y = x
A. y = x - 4
B.y = x + 4 \
C. y = -x + 4

Respuesta :

efawan
slope-intercept form: y = mx + c

First, from the given equation, we have slope m1 = 1. Then, we can find the slope for the perpendicular equation
[tex]m1 \times m2 = - 1 \\ 1 \times m2 = - 1 \\ m2 = - 1[/tex]
Then, we need to find the y-intercept
[tex]y = - x + c \\ 2 = - 2 + c \\ c = 2 + 2 \\ c = 4[/tex]
So, the perpendicular equation is:
[tex]y = - x + 4[/tex]

the line passing through point (2, 2) and perpendicular to the line whose equation is y = x

A. y = x - 4

B.y = x + 4 \

C. y = -x + 4

Answer:

C: y = -x + 4

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