Arcticatattack
Arcticatattack
23-01-2018
Mathematics
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What is the height for this problem?
Respuesta :
estherng0722
estherng0722
23-01-2018
Volume of cone = [tex] \pi r^{2}\frac{h}{3} [/tex]
h=3*[tex] \frac{Volume}{ \pi 2^{2} } [/tex]
=[tex]3* \frac{1/18}{ \pi * (\frac{2/3}{1/2}) ^{2} }[/tex]
=[tex]\frac{3}{32} \pi [/tex]ft
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