We have two points:
(-3,5) and (2,-3)
I
An equation in oint-slope form has this shape:
y-y₀=m(x-x₀)
m=slope
1) we compute the slope (m) between two points:
Given two points (x₁,y₁) and (x₂,y₂) the slope between these pointw will be.
m=(y₂-y₁)/(x₂-x₁)
In this case, our slope would be:
m=(-3-5)/(2+3)=-8/5
2) we choose one of these points and replace it in the equation, the result will be the same:
(-3,5)
y-y₀=m(x-x₀)
y-5=-8/5(x+3)
Answer: y-5=-8/5(x+3)
