brcardenas3 brcardenas3
  • 21-10-2017
  • Mathematics
contestada

Solve the equation on the interval [0, 2π).

cos x + 2 cos x sin x = 0

Respuesta :

chi3fcomm5nd
chi3fcomm5nd chi3fcomm5nd
  • 21-10-2017
take a common factor of cos(x)
[tex] \cos(x) (1 + 2 \sin(x) ) = 0[/tex]
then by zero multplication rules
[tex] \cos(x) = 0[/tex]
[tex]x = \frac{\pi}{2} \: x = \frac{3\pi}{2} [/tex]
and when
[tex]1 + 2 \sin(x) = 0[/tex]
so
[tex]2 \sin(x ) = - 1[/tex]
[tex] \sin(x) = \frac{ - 1}{2} [/tex]
so
[tex]x = \frac{3\pi}{2} - \frac{\pi}{3} [/tex]
and
[tex]x = \frac{3\pi}{2} + \frac{\pi}{3} [/tex]


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