Ellena980
Ellena980 Ellena980
  • 23-07-2015
  • Mathematics
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log9(x+6)-log9x=log9 2

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  • 23-07-2015
[tex]\log_9 (x+6)-\log_9 x=\log_9 2 \\ \\ \log_9 (\frac{x+6}{x})=\log_9 2 \\ \\ \log_9 (\frac{x+6}{x})-\log_9 2=0 \\ \\ \log_9 (\frac{x+6}{2x})=0 \\ \\ 9^0=\frac{x+6}{2x} \\ \\ 1=\frac{x+6}{2x} \\ \\ 2x=x+6 \\ \\ 2x-x=6 \\ \\ \boxed{x=6}[/tex]

Used properties of logarithms:
[tex]\log_a b - \log_a c=\log_a (\frac{b}{c}) \\ \hbox{if } \log_a b=c \hbox{ then } a^c=b[/tex]
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