Respuesta :
Refer to the figure below.
Define unit vectors as follows:
[tex]\hat{i}[/tex] in the eastern direction
[tex]\hat{j}[/tex] in the northern direction
Given:
Vectors a and b point due west and south respectively. Therefore
[tex]\vec{a} = -69 \ht{i} \\ \vec{b} = -69\hat{j}[/tex]
Part (a)
[tex]\vec{a}+\vec{b}=-69\hat{i}-69\hat{j}=-69(\hat{i}+\hat{j})[/tex]
The magnitude is
|-69(√[1² + 1²])| = 69√2 = 97.58.
The direction relative to west is
θ = tan⁻¹ (b/a) = tan⁻¹ 1 = 45° south of west
Answer:
The magnitude of (a + b) is 97.58 or 69√2.
The direction is 45° south of west.
Part (b).
[tex]\vec{a} - \vec{b} = -69\hat{i}+69\hat{j}=-69(\hat{i} -\hat{j})[/tex]
The magnitude is
|69(√(1+1)| = 69√2 = 97.58.
The direction relative to west is
tan⁻¹ (b/a) = 45° north of west.
Answer:
The magnitude of (a-b) is 97.58 or 69√2.
The direction is 45° north of west.
Define unit vectors as follows:
[tex]\hat{i}[/tex] in the eastern direction
[tex]\hat{j}[/tex] in the northern direction
Given:
Vectors a and b point due west and south respectively. Therefore
[tex]\vec{a} = -69 \ht{i} \\ \vec{b} = -69\hat{j}[/tex]
Part (a)
[tex]\vec{a}+\vec{b}=-69\hat{i}-69\hat{j}=-69(\hat{i}+\hat{j})[/tex]
The magnitude is
|-69(√[1² + 1²])| = 69√2 = 97.58.
The direction relative to west is
θ = tan⁻¹ (b/a) = tan⁻¹ 1 = 45° south of west
Answer:
The magnitude of (a + b) is 97.58 or 69√2.
The direction is 45° south of west.
Part (b).
[tex]\vec{a} - \vec{b} = -69\hat{i}+69\hat{j}=-69(\hat{i} -\hat{j})[/tex]
The magnitude is
|69(√(1+1)| = 69√2 = 97.58.
The direction relative to west is
tan⁻¹ (b/a) = 45° north of west.
Answer:
The magnitude of (a-b) is 97.58 or 69√2.
The direction is 45° north of west.
