Respuesta :

nicholasabner24
Molar mass of iron(III) oxide is 160g/mol

 160g ----------- of iron(III) oxide is ---------------- 6.02*10²³molecules
 79g   ----------- of iron(III) oxide is ---------------- x

x = [6.02*10²³*79g]/160g ≈ 2.97*10²³ molecules
kevinsolisd
160g ---------- 6·10²³molecules
  79g ----------          x

x = 2.9625·10²³ molecules

1molecule = 5 atoms
2.9625·10²³ molecules = 2.9625·10²³·5 = 14.8125·10²³ atoms