Answer:
Horizontal component of velocity is 8.81 m/s.
Explanation:
It is given that,
An athlete hurls a discus with a velocity of, v = 14 m/s
Angle with the ground, θ = 51°
We have to find the horizontal component of discus's velocity. The horizontal component of velocity is given by :
[tex]v_x=v\ cos\ \theta[/tex]
[tex]v_x=14\ m/s\times \ cos(51)[/tex]
[tex]v_x=8.81\ m/s[/tex]
Hence, the horizontal component of discus's velocity is 8.81 m/s.
