Glass has a specific heat of 0.16 calories/gram°C.
1.0 gram of glass will rise 20.0°C when _____ calories of heat are applied

Calories heat added = Mass of glass times temp. increase times specific heat of glass

calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/degree C = 3.2 calories

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raquecgomez raquecgomez · Answer 2 · 2019-09-06T03:59:47+02:00

Answer:

3.2 calories

Explanation:

The state of aggregation of the glass does not change, as its temperature increases, it is a sensible heat, because it depends on its temperature.

The sensible heat formula is

[tex]Q= m.sh.T[/tex]

[tex]sh= 0.16\frac{cal}{g C}[/tex]

[tex]m= 1.0 g\\T= 20C[/tex]

[tex]Q= 1.0 g.0.16\frac{cal}{gC} .20C\\ Q= 3.2 cal[/tex]

1.0 gram of glass will rise 20.0°C when 3.2 calories of heat are applied

Glass has a specific heat of 0.16 calories/gram°C. 1.0 gram of glass will rise 20.0°C when _____ calories of heat are applied

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Glass has a specific heat of 0.16 calories/gram°C.
1.0 gram of glass will rise 20.0°C when _____ calories of heat are applied