Nekofishy
Nekofishy
26-02-2017
Mathematics
contestada
x has 1 to 4 answers..
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ChandrikaP
ChandrikaP
26-02-2017
2sinxcosx=sin2x
sin(x) = sin(2x)
sin(x) = 2*sin(x)*cos(x)
0 = 2*sin(x)*cos(x) - sin(x)
2*sin(x)*cos(x) - sin(x) = 0
sin(x)(2*cos(x) - 1) = 0
sin(x) = 0 or 2*cos(x) - 1 = 0
sin(x) = 0 or 2*cos(x) = 1
sin(x) = 0 or cos(x) = 1/2
x = arcsin(0) or x = arccos(1/2)
x = pi*n or x = pi/3 + 2pi*n or x = -pi/3 + 2pi*n
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