DayDay774
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(4^p∙4^1)^3 simplifies to 4^q
Using the value of p that you solved for above, what is the value of the exponent q?
Explain how you found your answer. What law was used?

Respuesta :

[tex]\bf \left( 4^p\cdot 4^1 \right)^3\impliedby \textit{distributing the exponent} \\\\ \left(4^{p\cdot 3} \cdot 4^{1\cdot 3} \right)\implies 4^{3p}4^3\impliedby \begin{array}{llll} \textit{same base, different exponent}\\ \textit{add the exponents, keep the base} \end{array} [/tex]

what does it give you?

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