The Frequency will be "266.14 Hz" and the number of loops is "be 60".
Given:
Tension,
765 N
Length,
0.600 m
Mass,
4.50 g
As we know,
→ Linear density,
μ=[tex]mass/length[/tex]
By substituting the values, we get
4.5×10⁻³/0.6
=7.5×10⁻³
The fundamental frequency will be:
→ F=1/2L√T/μ
=266.14Hz
and,
The number of loops will be:
→ n=f'/f
=16000/266.14
=60
Thus the above response is correct.
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