Ok, here we have a right triangle so, we can use trigonometric ratios, in this case we could use the sine or the cosine since we know all the angles and a leg, and we need to find the hypotenuse. We choose to use the sine:
[tex]\sin (45)=\frac{\sqrt[]{3}}{x}[/tex][tex]\frac{\sqrt[]{2}}{2}=\frac{\sqrt[]{3}}{x}[/tex]
So, we are going to clear x:
[tex]x=\frac{\sqrt[]{3}\cdot2}{\sqrt[]{2}}=\sqrt[]{6}[/tex]
