It's important to know that the heat capacity of water is 4,200 Joules per Kilogram per degree Celsius. In order to answer the problem, we have to use the following formula
[tex]E=m\times c\times(T_f-T_i)[/tex]Replacing all the given information, we have
[tex]E=0.015kg\cdot4,200J/kgC\cdot(55-(-25))[/tex]Then, we solve the expression
[tex]\begin{gathered} E=63(55+25)Joules \\ E=63(80)Joules \\ E=5,040Joules \end{gathered}[/tex]