Respuesta :

Let:

h1 = Initial altitude = 0ft

h2 = Final altitude = -3ft

t1 = Initial time = 0s

t2 = Final time = 2s

[tex]change_{\text{ }}in_{\text{ }}altitude=\frac{h2-h1}{2-0}=\frac{-3-0}{2-0}=-\frac{3}{2}\frac{ft}{s}=-\frac{1.5ft}{s}[/tex]