Respuesta :

we have the equation

[tex]log(\frac{1,000}{253.95})=12tlog(1+\frac{0.08}{12})[/tex]

Solve for t

That means

Isolate the variable t

[tex]t=\frac{log(\frac{1,000}{253.95})}{12log(1+\frac{0.08}{12})}[/tex][tex]t=17.2[/tex]

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