Respuesta :

Solution:

Given the expression;

[tex]x^2+18x+c[/tex]

c is the half of square of coefficient of x. That is;

[tex]\begin{gathered} x^2+18x+c=x^2+18x+(\frac{1}{2}(18))^2 \\ \\ x^2+18x+c=x^2+18x+9^2 \\ \\ x^2+18x+c=x^2+18x+81 \\ \\ x^2+18x+81=(x+9)(x+9) \end{gathered}[/tex]

Hence, the value of c is;

[tex]c=81[/tex]

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