Here,
potential difference(V)= (2.00±0.02) V;
current (I)=( 5.3 ± 0.1) mA;
Resistance (X) will be given by
[tex]\begin{gathered} X=\frac{V}{I}; \\ X=\text{ }\frac{2.00±0.02}{5.3±0.1}\text{ }\times1000\begin{cases}V={(2.00±0.02)} \\ I=({5.3±0.1\text{ \rparen mA= \lparen5.3}\pm0.1)\times10^{-3\text{ }}}A\end{cases} \\ \\ \therefore X=(\text{ 377.358 }\pm0.001) \\ \text{ } \\ \end{gathered}[/tex]
