we have that
The trapezoidal approximation is equal to
[tex]A=\frac{1}{2}\cdot\lbrack f(a)+f(b)\lbrack\cdot(b-a)[/tex]
where
a=0
b=10
f(a)=f(0)=0.05
f(b)=f(10)=0.043
substitute given values
[tex]\begin{gathered} A=\frac{1}{2}\cdot\lbrack0.05+0.043\lbrack\cdot(10-0) \\ A=0.465\text{ m} \end{gathered}[/tex]
therefore
the answer is 0.465 meters
