The first term is a=10.
The number of terms is n=44.
The common difference is d=4.
The formula for the sum of n terms is,
[tex]S=\frac{n}{2}\lbrack2a+(n-1)d\rbrack[/tex]Determine the sum of first 44 terms of the series.
[tex]\begin{gathered} S=\frac{44}{2}\lbrack2\cdot10+(44-1)4\rbrack \\ =22\cdot\lbrack20+172\rbrack \\ =22\cdot192 \\ =4224 \end{gathered}[/tex]So answer is 4224.
