From 1 to 10, there are 3, 6, and 9 are divisible by 3
Then we have 3 choices out of 10 numbers
Since the probability = an event/outcomes
Since the event is 3
Since the outcomes are 10, then
[tex]P(\frac{no}{3})=\frac{3}{10}[/tex]This is the probability for spinning the spinner one time
But we need to spin it 70 times
We will multiply 3/10 by itself 70 times, which means make it to the power of 70
[tex]P(\frac{no}{3})=(\frac{3}{10})^{70}[/tex]The answer is (3/10)^70 OR (0.3)^70
