When x = 0, y = 2, then the constant term of the polynomial must be 2. This discards the last 2 options.
When x = 1, y = 11. Substituting x = 1 into the first two options, we get:
[tex]\begin{gathered} y=9\cdot1^2+2=9+2=11 \\ y=9\cdot1^2+11\cdot1+2=9+11+2=22 \end{gathered}[/tex]
Then, y = 9x² + 2 is correct.
