Respuesta :

EXPLANATION

Replacing the given functions into the following:

[tex]\frac{f(x+h)-f(x)}{h}[/tex][tex]\frac{x^2-1+h-(x^2-1)}{h}[/tex]

Removing the parentheses and simplifying:

[tex]\frac{x^2-1+h-x^2+1}{h}[/tex]

Simplifying like terms:

[tex]\frac{h}{h}=1[/tex]

Hence,

[tex]\frac{f(x+h)-f(x)}{h}=1[/tex]