HendryxB301601 HendryxB301601
  • 25-10-2022
  • Mathematics
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[tex]4(2 \times - 1) \ \textless \ (4 \times - 3)[/tex]That is the Math problem

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TehilaZ715493 TehilaZ715493
  • 25-10-2022
[tex]4(2x-1\text{ ) < 2(4x-3)}[/tex][tex]8x\text{ -4 < 8x -6}[/tex][tex]8x\text{ - 8x <-6 +4}[/tex][tex]\begin{gathered} so\text{ } \\ 8x\text{ - 8x = 0} \\ \text{therefore} \\ 0\text{ < -2} \\ \text{could it be the question is } \\ 4(2x-1)<4x\text{ - 1?} \\ \text{because the original questions makes little sense} \end{gathered}[/tex]

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