To solve this problem we can use the Ideal gas law:
[tex]\frac{P_1\cdot V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]The problem give us de following information:
P1= 131kPa
V1=1.82L
T1=-30°C= 243.15 K
P2= 233 kPa
V2= 1.3L
Then we just have to solve for T2 and use the information provided:
[tex]T_2=\frac{P_2\cdot V_2}{P_1\cdot V_1}\cdot T_1=\frac{233\text{ kPa}\cdot1.3L}{131kPa\cdot1.82L}\cdot243.15K=308.91K=35.76°C[/tex]Then the answer is T2=35.76°C
