Answer:
C
Step-by-step explanation:
[tex]\left(\frac{f}{g} \right)(x)=\frac{f(x)}{g(x)} \\ \\ \frac{f(x)}{g(x)}=\frac{\sqrt[3]{2x}}{2x+1}[/tex]
The denominator cannot equal 0, so:
[tex]2x+1 \neq 0 \implies x \neq -\frac{1}{2}[/tex]
