The resulting pH when 8.75 g of Ca(CH₃CH₂COO)₂ dissolves in enough water to give 0.500 L of solution.
The pH of the solution is = 9.08
Historically denoting "potential of hydrogen," is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions have lower pH values than basic or alkaline solutions.
To determine the initial concentration of propionate anions in solution, use the following formula:
[tex]\left[\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COO}^{-}\right]=\frac{\frac{17.5 \mathrm{~g}}{186.22 \mathrm{gmol}^{-1}}}{0.500 \mathrm{~L}}=0.188 \mathrm{M}[/tex]
At equilibrium: The equilibrium equation becomes
[tex]K b=\frac{x^2}{0.188-x}[/tex]
Using the small x approximation to solve for x:
[tex]\begin{gathered}K b=\frac{1.0 \times 10^{-14}}{1.3 \times 10^{-5}} \\K b=7.69 \times 10^{-10} \\7.69 \times 10^{-10}=\frac{x^2}{0.188} \\x=\sqrt{\left(7.69 \times 10^{-10}\right)(0.188)} \\x=\left[O H^{-}\right]=1.20 \times 10^{-5}\end{gathered}[/tex]
Verifying the approximation:
[tex]\frac{1.20 \times 10^{-5}}{0.188} \times 100 \%=6.38 \times 10^{-3} \%[/tex]
The approximation is correct because the value is less than 5%.
Calculating pH:
[tex]p O H=-\log 1.20 \times 10^{-5}[/tex]
pOH=4.92
pH=14−4.92
pH=9.08
The pH of the solution is = 9.08
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