jesmyers jesmyers

22-08-2022
Mathematics

contestada

solve for the interval [0,2pi): 1+sin θ= (√3+2)/2

Respuesta :

tgkim089 tgkim089

28-08-2022

Answer:

Step-by-step explanation:

1+sin(θ)=√3/2+2/2

sin(θ) = √3/2

on unit circle this is where y is positive because sin so it will be pi/3 and 2pi/3

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