The acute angles of a right triangle are complementary, so [tex]\boxed{m\angle F=34^{\circ}}[/tex].
Using right-angle trigonometry, we know that
[tex]\cos 56^{\circ}=\frac{26}{DF}\\\\DF=\frac{26}{\cos 56^{\circ}}\\\\\boxed{DF \approx 46.5}[/tex]
[tex]\tan 56^{\circ}=\frac{FE}{26}\\\\FE=26 \tan 56^{\circ}\\\\\boxed{FE \approx 38.5}[/tex]
