Answer:
Step-by-step explanation:
eq. of line x-3y-6=0
3y=x-6
y=1/3 x-6/3
or
y=1/3 x-2
its slope m1=1/3
y=2x+5
slope m2=2
if α is the angle between the lines then
[tex]tan~\alpha =|\frac{m1-m2}{1+m1m2} |=|\frac{\frac{1}{3} -2}{1+1/3\times 2}| =|\frac{1-3\times2}{3+2}| =5/5=1=tan 45\\\alpha =45^\circ\\[/tex]
