Answer:
See below
Step-by-step explanation:
cos 2pi/3 = -1/2
sin 2pi/3 = sqrt (3)/2
cos 1 pi/6 = sqrt(3)/2
sin 11 pi/6 = - 1/2
so when you put in these values in you will have :
(2*8) * (-1/2 + sqrt (3)/2 i )( sqrt(3)/2) + i (-1/2) )
= 16 ( - sqrt (3)4 + 1/4 i + 3/4 i - sqrt(3)/4 i^2 ) rememember i^2 = - 1
= 16 ( 1/4 i + 3/4 i )
= 16 i
