Answer:
Step-by-step explanation:
(h+k)(1)=h(1)+k(1)=2+(-1)=2-1=1
(k-h)(4)=k(4)-h(4)=0-(-1)=1
(k/h)(3)[tex]=\frac{k(3)}{h(3)} =\frac{-1}{0} =- \infty[/tex]
(h.k)(0)=h(0).k(0)=3(-2)=-6
(k.h)(0)=k(0).h(0)=-2(3)=-6
(h.k)(3)=h(3).k(3)=0(-1)=0
h(k(-2))=h(-3)=0
