viraliu0203 viraliu0203
  • 23-06-2022
  • Mathematics
contestada

Find all solutions of the equation in the interval [0, 2π).

Find all solutions of the equation in the interval 0 2π class=

Respuesta :

culveryolanda46
culveryolanda46 culveryolanda46
  • 23-06-2022

Answer:

x=0

Step-by-step explanation:

[tex]4 \cos(x) = - \sin {}^{2} (x) + 1[/tex]

[tex]4 \cos(x) = 1 - \sin {}^{2} (x) [/tex]

[tex]4 \cos(x) = \cos {}^{2} (x) [/tex]

[tex]4 \cos(x) - \cos {}^{2} (x) = 0[/tex]

[tex] \cos(x) (4 - \cos(x) ) = 0[/tex]

[tex] \cos(x) = 0[/tex]

[tex]x = 0[/tex]

[tex]4 - \cos(x) = 0[/tex]

[tex] \cos(x) = 4[/tex]

There is no solution here because cosine is undefined it the range is not between -1 and 1 so the only answer is 0.

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