Answer: [tex]y=\frac{1}{2}x+\frac{1}{2}[/tex]
Step-by-step explanation:
The line passes through (-1, 0) and (3,2), so the gradient is [tex]\frac{2-0}{3-(-1)}=\frac{1}{2}[/tex].
This means the equation of the line is of the form [tex]y=\frac{1}{2}x+c[/tex] for some constant c.
Substituting in the coordinates of the point (-1,0),
[tex]0=\frac{1}{2}(-1)+c\\\\0=-\frac{1}{2}+c\\ \\ c=\frac{1}{2}[/tex]
Thus, the equation of the line is [tex]y=\frac{1}{2}x+\frac{1}{2}[/tex]
