hmariee2248 hmariee2248
  • 21-06-2022
  • Mathematics
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What is the range of the function y=3√x+8?
0-∞ 0-8 O 0≤y<∞
O 2≤y<∞

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Medunno13
Medunno13 Medunno13
  • 30-06-2022

Answer: [tex]y \geq 8[/tex]

Step-by-step explanation:

The range of [tex]y=\sqrt{x}[/tex] is [tex]y \geq 0[/tex]

Multiplying this by 3, we get the range of [tex]y=3\sqrt{x}[/tex] is still [tex]y \geq 0[/tex]

Adding 8 to this, we get the range of [tex]y=3\sqrt{x}+8[/tex] is [tex]y \geq 8[/tex].

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