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A 0.034 kg copper rod is hung by two wires and placed in a constant magnetic field. A current
of 14 A runs through the 0.050 m long copper rod, making it hang at an angle of 34° from the
vertical as shown below.

What is the magnetic field strength holding the copper rod in this position?
The answer is B. Please show All work so I can see how to do it.

A 0034 kg copper rod is hung by two wires and placed in a constant magnetic field A current of 14 A runs through the 0050 m long copper rod making it hang at an class=

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onyebuchinnaji

The magnetic field strength holding the copper rod in this position is 0.39 T.

Magnetic field strength

The magnetic field strength holding the copper rod in position is calculated as follows;

F = BIL

where;'

  • F is the magnetic force = tension in the cord
  • B is magnetic field strength

F = mgcosθ

mg = BIL

B = (mgcosθ)/(IL)

B = (0.034 x 9.8 x cos34) / (14 x 0.05 )

B = 0.39 T

B = 3.9 x 10⁻¹ T

Learn more magnetic field here: https://brainly.com/question/7802337

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