a) The normal operating current through the resistor is 11.67A.
b) The resistance of the resistor is 10.286 Ω.
It is the essential electrical element used in the circuit to control the flow of current.
Given is the Power =1.40 x 10³ W and the voltage V=120V
a) P =VI
1.40 x 10³ = 120 x I
I = 11.67A
Thus, the current is 11.67A.
b) P =V²/R
1.40 x 10³= (120)² /R
R = 10.286 Ω
Thus, the resistance is 10.286 Ω.
Learn more about resistor.
https://brainly.com/question/24297401
#SPJ4
