Answer:
Explanation: to find the x-intercepts, that is the points on the x-axiswhere the graph crosses
x2−5x−24=0←in standard formfactorise the quadratic using the a-c methodthe factors of - 24 which sum to
- 5 are - 8 and + 3⇒(x−8)(x+3)=0equate each factor to zero and solve for
xx−8=0⇒x=8←x-interceptx+3=0⇒x=−3←x
-interceptgraph{x^2-5x-24 [-10, 10, -5, 5]}
