francelinecameu1234 francelinecameu1234
  • 23-04-2022
  • Chemistry
contestada

A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calculate the following: a. %m/m b. Molarity (M)

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okpalawalter8
okpalawalter8 okpalawalter8
  • 26-04-2022

For  the molarity and the  percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity  = 3.38M

What is the molarity?

Generally, the equation for the  percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity  = 0.0846mol/0.0250 L

molarity  = 3.38M

In conclusion, the molarity is given as

molarity  = 3.38M

Read more about Molarity

https://brainly.com/question/9149034

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