Respuesta :

hap092002
3(2-b)<10-3(b-6)
6-b<5(b-6)
6-b<5b-30
Let's make "b".......2
6-(2)<5(2)-30
4<10-30
4<-20
In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!
olorundaral
first you distribut the 3 into (2-b) 
then distribute -3 into (b-6)
to get 
6-3b<10-3b+18

then simplify

-3b+3b>10+18-6

 0>22